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modulo

英['mɒdjʊləʊ] 美['mɒdjəˌloʊ]
  • prep. 关于模数

双语例句

1. Group of units of order 2pq of modulo n residue class ring.
单位群的阶为2pq的模n剩余类环。

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2. The Checksum Word contains the twos complement of the modulo 256 sum of the.
校验字包含两个数据信息的和与256的模的两个补码。

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3. Use unsigned types only when you need modulo arithmetic or very very large Numbers.
仅在你需要模算术或需要很大很大的数字时,才使用无符号类型。

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4. The cipher blocks are obtained by 8 rounds of substitution and the Modulo-Plus function.
密文块是通过8轮的替换和模加运算得到的。

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5. Spread spectrum was conducted first, and then it was embedded into watermark by means of integer modulo.
嵌入水印时,先对水印信息进行扩频,再利用基于模运算的方法嵌入水印。

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6. This technique requires a variable modulo counter, another counter for the selection, and logic for state control.
这技术以柜台为模需要一个变数,另外的一个柜台为选择,和逻辑对于州控制。

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7. In Chapter 4, several problems are involved in linear codes over finite fields with two dimensional modulo metrics.
在第四章中,考虑在两种二维距离之下有限域上线性码的几个问题。

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8. Use modulo to simulate rolling the wheel: $result1 = $wheel1[rand(count($wheel1), 10*count($wheel1)) % count($wheel1)];.
使用模数来模拟滚动转轮:$result1 = $wheel1[rand(count($wheel1),10*count($wheel1)) % count($wheel1)];。

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9. Or Modulo - the modular steam heat exchanger in copper exclusively: With unit advantages for flexibility and efficiency.
或模-组合式蒸汽换热器铜独家:单位优势,灵活性和效率。

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10. The analysis and example indicted that the design method is feasible. It develops the way of design modulo-N counter with MSI.
分析与设计举例表明该设计方法是可行的,它拓宽了采用MSI设计任意进制计数器的途径。

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11. Running this code verifies that exponentiation works (modulo the bug I mentioned earlier), so half of the battle is now complete.
运行这段代码确保可以求幂(忽略我之前提到的bug),这样就完成了一半的工作。

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12. If it is already there then it doesn't matter, modulo a possible buffer overrun, if not then you avoided your program using bad data.
如果它已经存在并没关系,模可能的缓冲区溢出,如果没有的话,你可以避免你的程序使用错误的数据。

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13. Your best bet in situations like this is to operate on absolute values when doing modulo operators if you want basic integer division.
在这种情况下你最好的选择是使用绝对值做模运算符时如果你想基本整数的除法。

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14. Thus, the server never does anything more complicated than the simple one-step diamond divergence (modulo some operation composition).
因此,服务器永远不用负责比单步菱形分歧更复杂的问题(操作组合的模型)。

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15. Because only Numbers between 0 and 128 specify MIDI pitches, you can then convert this number to a MIDI pitch by taking its value modulo 128.
因为只有0和128之间的数指定midi音高,所以可以通过将这个数值取128的模将它转换为midi音高。

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16. Now, if you don't like the idea of performing divisions mentally, there's hope: you don't really need to divide by 7 to get the number's modulo.
如果你不喜欢心算做除法,还有一种办法:不用真的取除以7取余数。

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17. On the other hand, we are aimed to remove the memory redundancy of the previous linear skewing interleave scheme and try to support modulo addressing.
在另一方面,本文致力于研究如何改进传统的基于线性偏差的地址交织策略来解决其存储器冗余和无法支持模寻址的问题。

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18. Finally, through the analysis and comparison with other kind of modulo adders, we draw the conclusion that the performance of the new modulo adder is better.
最后,通过与其它模加法器在结构以及算法等方面进行分析比较,表明本文所设计的模加法器性能优异。

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19. Polynomial modulo reduction algorithms are one of the fundamental issues of computer algebra, and widely used in coding algorithms and cryptographic system design.
多项式模归约算法是计算机代数中的基本问题之一,在编码算法和密码体制设计中有着广泛应用。

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20. In this paper, we have studied the asymptotic formula of a number theoretic function about the primitive roots modulo n, and given a more precise asymptotic formula.
研究一个关于n原根的数论函数的渐近性质,给出了一个较为精确的渐近公式。

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21. Generally, this problem is reduced to quadratic residue problem of modulo a big prime number. But this reduction is not applicable to Optimal Extension Fields (OEF).
一般而言,该问题归结为模大素数的二次剩余问题,但这种归结不能用于最优扩域OEF。

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22. This paper proposes the design method of a mixedvalued modulo-N synchronous counter by using both common binary flip-flops and ternary T flip-flops which has binary structure.
提出用纯二值结构的三值T触发器和普通的二值触发器一起构造混值N进制计数器的设计方案。

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23. Since the % character is used extensively by the macro preprocessor, you should ensure that both the signed and unsigned modulo operators are followed by white space wherever they appear.
因为%被宏预处理器广泛使用,你要确保有符号或无符号求余运算符应该紧跟着空格。

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24. This paper analyses the coupling wastage in columniform wave guide gas laser, and gives the function between the coupling wastage of laser guide modulo EH11 and the position and radius of reflector.
分析了圆柱形波导气体激光器中的耦合损耗,给出了最低阶波导模EH11的耦合损耗与反射镜位置、曲率半径的函数关系。

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25. This paper analyses the coupling wastage in columniform wave guide gas laser, and gives the function between the coupling wastage of laser guide modulo EH11 and the position and radius of reflector.
分析了圆柱形波导气体激光器中的耦合损耗,给出了最低阶波导模EH11的耦合损耗与反射镜位置、曲率半径的函数关系。

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